The problem has an infinite number of solutions. A couple of them are (x, y) =

(4, 1)

(13, 5)

To find one of the solutions, pick a value for x or y, put it in the equation in place of the variable, and solve for the other variable by undoing the operations.

Example

Choose y = 1

4x - 9*1 = 7 (we put 1 where y was)

4x - 9 = 7 (perform the multiplication)

4x - 9 + 9 = 7 + 9 (undo the subtraction of 9 by adding 9 to both sides)

4x = 16 (perform the addition)

4x/4 = 16/4 (undo the multiplication by 4--by dividing both sides by 4)

x = 4 (perform the division)

(4, 1)

(13, 5)

To find one of the solutions, pick a value for x or y, put it in the equation in place of the variable, and solve for the other variable by undoing the operations.

Example

Choose y = 1

4x - 9*1 = 7 (we put 1 where y was)

4x - 9 = 7 (perform the multiplication)

4x - 9 + 9 = 7 + 9 (undo the subtraction of 9 by adding 9 to both sides)

4x = 16 (perform the addition)

4x/4 = 16/4 (undo the multiplication by 4--by dividing both sides by 4)

x = 4 (perform the division)