Determine the slope of the line through points (0, -4) and (5, -9)

X^2+6x-8 / x-2

4x-2=6x+4

-91=9+8

X^2-6x=-8

x^2-6x+8=0

x^2-4x-2x+8=0

x(x-4)-2(x-4)=0

(x-2)(x-4)=0

x=2,4

x^2-6x+8=0

x^2-4x-2x+8=0

x(x-4)-2(x-4)=0

(x-2)(x-4)=0

x=2,4

Add 8 to both sides, then factor

x

(x-4)(x-2) = 0

This will be true if either of the factors is zero.

X-4 = 0

x = 4

x-2 = 0

x = 2

x

^{2}- 6x + 8 = 0(x-4)(x-2) = 0

This will be true if either of the factors is zero.

X-4 = 0

x = 4

x-2 = 0

x = 2

**The solutions to the equation are x = 2 or 4.**