X

x

x

(x + 5)(x - 5) = 0 (factor)

Likewise, we can eliminate the exponent by taking the square root of both sides:

X

√x

√x

^{2}= 25 (your statement)x

^{2 }- 25 = 25 - 25 (subtract 25 from both sides)x

^{2}- 25 = 0 (collect terms)(x + 5)(x - 5) = 0 (factor)

**From the above we can deduce that ±5 are real solutions.**Likewise, we can eliminate the exponent by taking the square root of both sides:

X

^{2}= 25 (your statement)√x

^{2}= √25 (take thr square root)**x = ±5****______**x^{2}= 30 (your statement)√x

^{2 }= √30 (eliminate the exponent by taking the square root of both sides)**x = ±(√30)**