How To Solve The Quadratic Equation By Completing The Square. Y^2-5y+4=0?

1 Answers

amber Jhon Profile
amber Jhon answered
Y^2-5y+4=0

y^2-5y=-4

adding (5/2)^2 on both sises to complete the square

y^2-5y+(5/2)^2=-4+(5/2)^2

(y-5/2)^2=-4+25/4

(y-5/2)^2=-16+25 /4

(y-5/2)^2=9/4

squaring on both sides

(y-5/2)=+3/2

y=5/2+3/2

y=5/2+3/2;  y=5/2-3/2

y=4 ; y=1

thanked the writer.
Oddman
Oddman commented
On one line of your solution, you have ()= -4 + 25/4
On the next line of your solution, you have ()= -16 + 25/4.
Methinks some parentheses should be involved: (-16 + 25)/4

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