We know that (x+a)2 = x2 + 2ax + a2, so we know that a is half the coefficient of the x term.
2a = -16
a = -16/2 = -8
If we add a2 to both sides of the equation, we can complete the square.
x2 - 16x + 15 = 0
x2 - 16x + 64 + 15 = 64 (we have added 64 so we can complete the square)
(x-8)2 + 15 = 64
Solution:
(x-8)2 = 64 - 15 (subtract 15 from both sides)
(x-8)2 = 49 (This may be the form you prefer for the equation with the square complete.)
x - 8 = ±√49 (take the square root of both sides)
x = 8 ± 7 (add 8 to both sides)
x = {1, 15}
Check 1
We know the factors of a quadratic are (x-root1)(x-root2)
(x-1)(x-15) = x2 -15x -1x +15 = x2 -16x +15 (original equation. This checks both roots at once.)
Check 2
Try the roots one at a time.
(1)2 -16(1) +15 = 0 (x=1)
1 - 16 + 15 = 0 (yes)
(15)2 - 16(15) + 15 = 0 (x=15)
15(15 - 16 + 1) = 0 (yes)
2a = -16
a = -16/2 = -8
If we add a2 to both sides of the equation, we can complete the square.
x2 - 16x + 15 = 0
x2 - 16x + 64 + 15 = 64 (we have added 64 so we can complete the square)
(x-8)2 + 15 = 64
Solution:
(x-8)2 = 64 - 15 (subtract 15 from both sides)
(x-8)2 = 49 (This may be the form you prefer for the equation with the square complete.)
x - 8 = ±√49 (take the square root of both sides)
x = 8 ± 7 (add 8 to both sides)
x = {1, 15}
Check 1
We know the factors of a quadratic are (x-root1)(x-root2)
(x-1)(x-15) = x2 -15x -1x +15 = x2 -16x +15 (original equation. This checks both roots at once.)
Check 2
Try the roots one at a time.
(1)2 -16(1) +15 = 0 (x=1)
1 - 16 + 15 = 0 (yes)
(15)2 - 16(15) + 15 = 0 (x=15)
15(15 - 16 + 1) = 0 (yes)