The quadratic formula tells you the solution to ax^2 + bx + c = 0 is given by x = (-b ± √(b^2 - 4ac))/(2a)

You have an equation in which a=6, b=3, c=-18, so the formula gives x = (-3 ± √(3^2 - 4(6)(-18))/(2*6) x = (-3 ± √(9+432))/12 x = (-3 ± √441)/12 x = (-3 ± 21)/12 x = {-24/12, 18/12} x = {-2, 3/2}

Shelia, first let's see what the quadratic formula is, ok?

x = [-b ±√b^{2}-4ac]/2a

Now, write out your equation: 6x^{2} + 3x -18 = 0

The values from the quadratic formula that we extract from this equation are:

a = 6 b = 3 c = -18

Now, all you have to do is put these values in the quadratic formula and you will get your answer x = [-b ±√b^{2}-4ac]/2a

x = [-3 ±√3^{2}-4.6.-18]/2.6 (I am using a period to show a multiplication sign so that you do not confuse it with 'x' in the equation)

x = [-3 ± √9 + 432]/12 x = [-3 ± √441]/12 x = [-3 ± 21]/12

Now, the '±' sign shows that the value can be either positive or negative.

So, we will solve for each. Now our two new equations are:

x = [-3 + 21]/12 x = 1.5

and

x = [-3 - 21]/12 x = -2

So, the two values for x are 1.5 and -2.

About how we type all the mathematical symbols, I use MS-Word for that. You can also use MS-Excel if you want to. Go to 'Insert' and choose 'Symbols'. Here, you would only be given a few options but an option would say, 'More symbols'. Choose that and you would probably find the symbol you are looking for. I use MS-Office 2007. This also has inbuilt equations that you can choose from Insert 'Equations'. I think previous issues of Word would also have them. You just need to browse around a little. Use 'x' or '*' to show multiplication. You can square a number/ alphabet by writing it, like x2. Then select 2 and click on x^{2} on the tool bar to make it a superscript. I think it would all be very clear to you now. Have fun!

Since the question mentions the quadratic formula, the problem should probably read 6x^{2} + 3x – 18 = 0. The quadratic formula is shown in the picture. Following the formula, X= (-3+(SQRT(9-4*6*(-18))))/12 and x = (-3-(SQRT(9-4*6*(-18))))/12. Or, doing the arithmetic, x=1.5 and x=-2.

Here is your quadratic equation : 6x2 + 3x – 18 = 0 therefore 6x(square)+12x-9x-18=0 6x(x+2)-9(x+2)=0 (6x-9)(x+2) = 0 therefore 6x-9 =0 and x+2=0 therefore x=9/6 and x=-2 so the correct answer is x = {3/2, -2} rough work 18 * 6 = 108 now can we take 12 * 9 like +12 and -9, which will sum up and give +3{between} and the product 108{ product of first and the last 18 * 6 }