What Is The Vertex, Quadratic Function In Standard Form, Axis Of Symmetry, X-intercepts Of The Following Function?

1 Answers

amber Jhon Profile
amber Jhon answered
F(x)= -4x2-8x+12

For finding the Vertex of the equation:

y - 12 = -4(x2+2x)

y - 12 = -4(x2+2x+1-1)

y - 12 = -4{(x2+2x+1)-1}

y - 12 = -4{(x + 1)2-1}

y - 16 = -4(x + 1)2

Vertex = (1,-16)

The standard form:

The standard form of parabola is y - 16 = -4(x + 1)2

Axis of symmetry:

Axis of symmetry in this equation is -1.

For x-intercept:

Put y = 0 for x-intercept therefore,

0 - 16 = -4(x + 1)2

4 = (x + 1)2

Taking square root on both sides:

2 = x + 1

x = -1

Answer Question

Anonymous