I suppose "vertex form" for your function would be

F(x) = a(x-h)^2 + k

where (h, k) is the vertex.

We can rewrite your equation as

F(x) = 2(x^2 - 6x) + 17

We can add and subtract 18 to get this into vertex form

F(x) = 2(x^2 - 6x

F(x) = a(x-h)^2 + k

where (h, k) is the vertex.

We can rewrite your equation as

F(x) = 2(x^2 - 6x) + 17

We can add and subtract 18 to get this into vertex form

F(x) = 2(x^2 - 6x

**+ 9**) + 17**- 18****F(x) = 2(x-3)^2 - 1 for vertex = (3, -1)**