How to convert y=1/3(x-1)^2+2 to vertex form?

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Oddman Profile
Oddman answered
Some would say the equation is already in vertex form. For others, you need to subtract 2
  y-2 = 1/3(x-1)^2
Where the vertex is (h, k), vertex form shows these values explicitly
  y-k = a(x-h)^2
  y = a(x-h)^2 + k

The first of these forms is the one I learned. It is readily recognized as a translation of
  y = ax^2
to a new vertex position.

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