Find the vertex of the parabola. Y = -2x^2 + 12x - 13?

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Oddman Profile
Oddman answered
For the parabola
  y = ax^2 + bx + c
The x value of the vertex is given by
  x = -b/(2a)
For your parabola, this is
  x = -(12)/(2*(-2)) = 3
The value of y at that point is
  y = -2(3^2) + 12(3) - 13
  = -2*9 + 36 - 13
  = 5
The vertex is located at (x, y) = (3, 5).
Michael Knudsen Profile
Michael Knudsen answered
When x=3.. Not sure, because I tried using derivatives and equating the first derivative to 0 and finding x.. Then plug x=3 into the original equation and Y should be 5... (I don't remember parabolas)

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