When the function is written in the form ax

x = -1/2 at the vertex. F(-1/2) = (-1/2)

The vertex is (-1/2, -2 1/4).

F(x) = x

F(1) = 0

F(-2) = 0

F(0) = -2

^{2}+bx+c, the vertex is given by -b/2a.x = -1/2 at the vertex. F(-1/2) = (-1/2)

^{2}+ (-1/2) - 2 = -2 1/4The vertex is (-1/2, -2 1/4).

F(x) = x

^{2}+ x - 2 = (x-1)(x+2)F(1) = 0

F(-2) = 0

F(0) = -2