Can You Find The Vertex And Intercepts Of The Function F(x) =x2+x-2.?

When the function is written in the form ax²+bx+c, the vertex is given by -b/2a.

x = -1/2 at the vertex. F(-1/2) = (-1/2)² + (-1/2) - 2 = -2 1/4

The vertex is (-1/2, -2 1/4).

F(x) = x² + x - 2 = (x-1)(x+2)
F(1) = 0
F(-2) = 0
F(0) = -2