F(x)=x^2+x-2, What Is The Vertex And Intercepts Of This Function,Can You Help Me?

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Anonymous answered
Let's assume the equation is F(x) = x2 + x - 2.  You had a minus sign in there.

To determine the intercepts at F(x) = 0, simply set the equation equal to zero and solve.

x2 + x - 2 = (x + 2)(x - 1)

(x + 2)(x - 1) = 0

Roots are x = -2, x = 1.

To find the vertex, take the derivative and set it equal to zero, solve for the x and F(x) values.

F'(x) = 2x + 1

2x + 1 = 0

x  = -1/2

F(-1/2) = (-1/2)2 + -1/2 - 2

  .     = 1/4 - 1/2 - 2

  .     = -5/4

The vertex is at (-1/2, -5/4)

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