Translating the given equation to intercept form by dividing by 12, we see that it has a y-intercept of (0,

X/12 + y/

Thus, your problem reduces to finding the slope of the line through (5, 4) and (0, 3).

Slope = ∆y/∆x = (4-3)/(5-0) = 1/5

X + 4y = 12

0 + 4y = 12 (make the substitution)

4y = 12 (simplify)

y = 12/4 (divide both sides by 4)

y = 3

**3**). Intercept form is**x/(x-intercept) + y/(y-intercept) = 1**.X/12 + y/

**3**= 1Thus, your problem reduces to finding the slope of the line through (5, 4) and (0, 3).

Slope = ∆y/∆x = (4-3)/(5-0) = 1/5

##### Your "linear function" has a slope of 1/5 and a y-intercept of (0, 3).

Another way to determine the y-intercept is to substitute x=0 and solve for y.X + 4y = 12

0 + 4y = 12 (make the substitution)

4y = 12 (simplify)

y = 12/4 (divide both sides by 4)

y = 3