A)solve 5x+4y=12 For Y

Question

A)solve 5x+4y=12 For Y

5 Answers

Answer Question

Answer 1

To solve this equation, assume a range of values for x (say from -3 to +3). Substitute the value of x in the given equation to calculate the corresponding value of y. Repeat the procedure for each value of x in the range. Plot the set of values on a graph.

The y value of the point where the graph cuts the y-axis is the y-intercept.

To calculate the value of y when x = 16
5(16) + 4y = 12
4y = -68
y = -17

Answer 2

Solving the equation for y puts it into slope-intercept form, making it easy to answer the questions.
5x + 4y = 12
4y = 12 - 5x (subtract 5x from both sides)
y = (-5/4)x + 3 (divide both sides by 4. This is y=mx+b form where m is slope, b is y-intercept.)

The slope is -5/4.
The y-intercept is 3.
The value of y when x=16 is -17. (y=-5/4*16+3 = -20+3)

Answer 3

To solve for y in this equation

5x+4y=12

we can write it as

y = ( 12 - 5x)/4

solve for why by substituting different values for x.

Answer 4

Y = (5/4) x - 3
therefore the gradient will be 5/4 and y intercept will be - 3
hope that helps :)

Answer 5

Sending +5x to other side of the equation>>> 4y=12-5x
, Sending 4 to other side of the equation >>> y=(12-5x)/4

I'll pick a couple values for x, and find the values for y. Picking x = 2, I get y = 1/2
= Picking x = -2, I get y = 11/2. Then the points (2, 1/2) and
(-2, 11/2) are on the line y=(12-5x)/4. The slope of the line is then calculated as:

M = y2-y1 / x2-x1 = (11/2 - 1/2 ) / -2 - (-2)

m = 5/0
m = infinity that means the line is parallel to vertical axis.

When x = 16 , y = 12-80/4 = -68/4 = -17

:)