# Given the linear equation y = -4/7x - 5, find the y-coordinates of the points (-7, ), (0, ), and (7, )?

-4/7*(-7) - 5 = +4 - 5 = -1. The first point is (-7, -1).

-4/7*(0) - 5 = -5. The second point is (0, -5).

-4/7*(7) - 5 = -4 - 5 = -9. The third point is (7, -9).

The slope of -4/7 means that for each increase of 7 in x, y will decrease by 4. We see that the points of interest have x increasing by 7 and y decreasing by 4. Here is a plot.
thanked the writer.
Oddman commented
If y=-4/(7x), the equation is not a "linear equation". When you disagree with both the description of the problem and with its answer, perhaps your interpretation needs to be adjusted.
falak commented
No what i am saying is -4/7x makes a reciprocal function and a linear eq would not be written to show x right with 7 so that it seems to be part of the denominator. Rather like
-4/7 x or (-4/7)x.
falak commented
And as i already said below, you can refer to the standard edexcel or cie papers or any math book if you dont agree with me. You would never find one inshAllah with x written right up with the denominator constant.
Salam (peace)
You need to put the x coordinates in the equation and solve it for the value of y.
1- y=-4/7(-7)-5
=4/49-5
=-4.91
2- y=-4/7(0)-5
=undefined as 4 (or any other number even) divided by 0 is undefined
3-y=-4/7(7)-5
=-4/49-5
=-5.08
hope it helps. Khuda Hafiz...
thanked the writer. 