The numbers are 2 and 18.
If the lcm is 18 and hcf is 2 wHAT R THE NUMBERS? HOW DID U GET THE RESULT?(WHICH METHOD)
You need to find 3 numbers that multiply to 18, but you are given one of them. In other words, you need to find x and y such that
x*2*y = 18
One of your numbers will be x*2. The other of your numbers will be 2*y. You are not allowed to choose x and y such that they have any common factors.
From the above equation, we know that
x*y = 9
From our math facts, we know that
9 = 1*9 = 3*3
Of these factor pairs, we eliminate 3, 3 because they have 3 as a common factor. Thus, choices for your two numbers are (x, y) = (1, 9)
1*2 = 2, 9*2 = 18 {2, 18} is the only solution to your problem
x*2*y = 18
One of your numbers will be x*2. The other of your numbers will be 2*y. You are not allowed to choose x and y such that they have any common factors.
From the above equation, we know that
x*y = 9
From our math facts, we know that
9 = 1*9 = 3*3
Of these factor pairs, we eliminate 3, 3 because they have 3 as a common factor. Thus, choices for your two numbers are (x, y) = (1, 9)
1*2 = 2, 9*2 = 18 {2, 18} is the only solution to your problem