How to factor 16x2-88x+121?

2 Answers

John McCann Profile
John McCann answered
I assume you mean;

16X^2 -88X + 121 = 0

even if you did not I am not going to factor that monster, but use the quadratic formula

discriminant: (-88)^2 - 4(16)(121)

= 7744 - 7744 = 0

one real root indicated, next

X = - b (+/-) sqrt(b^2-4ac)2a

a = 16
b = -88
c = 121

X = - (-88) (+/-) sqrt[(-88)^2 - 4(16)(121)]/2(16

X = 88 (+/-) sqrt(7744 - 7744)/32

X =  88/32

X = 11/4

which is 2.75
Oddman Profile
Oddman answered
A clue is offered by the fact that the first and last terms are perfect squares.
  16x^2 - 88x + 121
  = (4x - 11)^2

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