The equation you wrote has the solution found here. The only integer solution is x=0.

Maybe you want the answer to

(5^2)^(2x) = (5^4)*(5^3)^x

5^(4x) = 5^(4+3x) (use various rules of exponents)

Taking logs to the base 5, we have

4x = 4+3x

Maybe you want the answer to

**25^(2x) = 625*125^x**We can rewrite this as(5^2)^(2x) = (5^4)*(5^3)^x

5^(4x) = 5^(4+3x) (use various rules of exponents)

Taking logs to the base 5, we have

4x = 4+3x

**x = 4**(subtract 3x)