The equation you wrote has the solution found here. The only integer solution is x=0.
Maybe you want the answer to
25^(2x) = 625*125^x We can rewrite this as
(5^2)^(2x) = (5^4)*(5^3)^x
5^(4x) = 5^(4+3x) (use various rules of exponents)
Taking logs to the base 5, we have
4x = 4+3x
x = 4 (subtract 3x)
Maybe you want the answer to
25^(2x) = 625*125^x We can rewrite this as
(5^2)^(2x) = (5^4)*(5^3)^x
5^(4x) = 5^(4+3x) (use various rules of exponents)
Taking logs to the base 5, we have
4x = 4+3x
x = 4 (subtract 3x)
