You can do this a number of ways. The simplest is to decompose 4 into a sum.

4 = 1 + 3

4 = 2 + 2

The ancient Egyptians (and some other civilizations) made use of what we now call "Egyptian Fractions" to write fractions with a numerator greater than 1. They would, for example, write 2/5 as the sum

2/5 = 1/3 + 1/15

They had a simple algorithm for finding such sums good with fractions of the form 2/n. In your problem, however, we have double this amount.

4/5 = 2(2/5) = 2(1/3 + 1/15) = 2/3 + 2/15

Applying the 2/n algorithm again, we find that

4/5 = 2/3 + 2/15 = (1/2 + 1/6) + (1/10 + 1/30)

Thus, a decomposition of 4/5 into Egyptian Fraction form is

It is unlikely you are expected to know anything about Egyptian Fractions, but they are an interesting way to work your problem. (At the link above is a section on how to compute them when the denominator is prime (3, 5) and when it is not (15).)

4 = 1 + 3

**4/5 = 1/5 + 3/5**Or4 = 2 + 2

**4/5 = 2/5 + 2/5**The ancient Egyptians (and some other civilizations) made use of what we now call "Egyptian Fractions" to write fractions with a numerator greater than 1. They would, for example, write 2/5 as the sum

2/5 = 1/3 + 1/15

They had a simple algorithm for finding such sums good with fractions of the form 2/n. In your problem, however, we have double this amount.

4/5 = 2(2/5) = 2(1/3 + 1/15) = 2/3 + 2/15

Applying the 2/n algorithm again, we find that

4/5 = 2/3 + 2/15 = (1/2 + 1/6) + (1/10 + 1/30)

Thus, a decomposition of 4/5 into Egyptian Fraction form is

**4/5 = 1/2 + 1/6 + 1/10 + 1/30**______It is unlikely you are expected to know anything about Egyptian Fractions, but they are an interesting way to work your problem. (At the link above is a section on how to compute them when the denominator is prime (3, 5) and when it is not (15).)