This is a binomial distribution

the probability of a 2 (T) is 1/6 __ the probability of NOT a 2 (N) is 5/6

for five rolls, one 2 __ 5(T^1*N^4) __ 5 * (1/6) * (5/6)^4 __ .402 (approx)

Answer is .402

the probability of a 2 (T) is 1/6 __ the probability of NOT a 2 (N) is 5/6

for five rolls, one 2 __ 5(T^1*N^4) __ 5 * (1/6) * (5/6)^4 __ .402 (approx)

Answer is .402