Probability = No. Of favorable ways / Total ways

where ,

Total ways = no. Of favorable ways + no. Of non-favorable ways

Since, odd no. + odd no. = even no.even no. + even no. = even no.

odd no. + even no. = odd no.

according to question, sum of numbers is odd -

Hence, one dice should show an even number like 2 or 4 or 6 an other dice should show an odd number 1 or 3 or 5.

making all pairs as --- ( no. On 1st dice , no. On second dice )

(1 , 2) (2, 1) (1 , 4) (4, 1) (1, 6) (6, 1)

(3, 2) (2, 3) (3, 4) (4, 3) (3, 6) (6,3)

(5, 2) (2,5) (5,4) (4,5) (5,6) (6,5)

No. Of Favorable ways (pairs) = 6 + 6 + 6 = 18

Total ways = ways of any no. Showing on dice 1 x ways of any no. Showing on dice 2 = total no. Of Pairs

( when 2 process occur simultaneously independently then their no. Of ways are multiplied )

= 6 x 6 = 36

hence probability = Favorable ways / Total ways

= 18 / 36 = 1/2 = 0.5