5y(2x-1) = y(x+2) + 20
I assume you are looking for Y. X = 3.
5Y[2(3) - 1] = Y[(3) + 2) + 20
5Y(6 - 1) Y(3 + 2) + 20
Distribute the Y terms to parentheses.
30Y - 5Y = 3Y + 2Y + 20
25Y = 5Y + 20
20Y = 20
Y = 1
======You can check it visually and this answer is correct.
