3^(5x-4) * a^(4x-3) = 3^(2x-3) * a^(x-2)
3^(5x-4) / 3^(2x-3) = a^(x-2) / a^(4x-3)
3^(5x-4-2x+3) = a^(x-2-4x+3)
3^(3x-1) = a^(-3x+1)
From this, we can deduce that a = 1/3. However, x can essentially be anything. Even when we plug back what "a" is into the original equation, all you get is 3^(x-1) = 3^(x-1) which doesn't really help you solve x either. So this is all that I can deduce from what you've given me. I'm sorry if it wasn't much help.
