Equation 1:
y=6x+2
Equation 2:
y=x+17
Equation 2 can also be written as:
x=y-17
Lets suppose this is equation 3
So:
Substituting equation 3 into equation 1;
y=6(y-17)+2
Expanding:
y=6y-102+2
Adding:
y=6y-100
Shifting 6y to the other side:
y-6y=-100
subtracting:
-5y=-100
dividing:
-y=-100/3
So:
-y=-33.33
Canceling the minus sign we get:
y=33.33
So the value of y is 33.33
To find the value of x lets substitute this value into equation 3. Hence:
x=y-17
x=33.33-17
Subtracting:
x=16.33
Hence the vale of x is 16.33
y=6x+2
Equation 2:
y=x+17
Equation 2 can also be written as:
x=y-17
Lets suppose this is equation 3
So:
Substituting equation 3 into equation 1;
y=6(y-17)+2
Expanding:
y=6y-102+2
Adding:
y=6y-100
Shifting 6y to the other side:
y-6y=-100
subtracting:
-5y=-100
dividing:
-y=-100/3
So:
-y=-33.33
Canceling the minus sign we get:
y=33.33
So the value of y is 33.33
To find the value of x lets substitute this value into equation 3. Hence:
x=y-17
x=33.33-17
Subtracting:
x=16.33
Hence the vale of x is 16.33