You have not said what solution you seek.

A

y = x + b'

-7 = 2 + b' substitute the values at the given point

-9 = b' subtract 2

Your equation is

A

-1/1 = m' = -1

So the perpendicular line will have the form

y = -x + b' where b' is the intercept that makes the line go through the given point

-7 = -(2) + b' substitute the values at the given point

-5 = b' add 2

Your equation is

The

d = |y - x + 2|/√(1^2 + (-1)^2) = |-7 - 2 + 2|/√2 =

A

**parallel line**through the point will have the same slope, but a different intercept. The new intercept (b') will satisfy the equationy = x + b'

-7 = 2 + b' substitute the values at the given point

-9 = b' subtract 2

Your equation is

**y = x - 9**.A

**perpendicular line**through the point will have a slope (m') that is the negative inverse of the slope of your line, which is 1.-1/1 = m' = -1

So the perpendicular line will have the form

y = -x + b' where b' is the intercept that makes the line go through the given point

-7 = -(2) + b' substitute the values at the given point

-5 = b' add 2

Your equation is

**y = -x - 5**.The

**distance from the point to the line**isd = |y - x + 2|/√(1^2 + (-1)^2) = |-7 - 2 + 2|/√2 =

**(7/2)√2**