3/5 ?>? 4/6
this can be done in many ways:
1. Number line(can't really display it here)
2. Use least common multiple on of the denominators so we can force them to be the same
you can start with the product of them:
5 * 6 = 30
so we multiply the left side of the inequality by 6/6 (it must be equivalent to 1 in order to maintain balance) and the right side by 5/5
(6/6)(3/5) ?>? (5/5)(4/6)
18/30 ?>? 20/30
so we know that 20 > than 18, so the answer to the question is NO
it should be:
3/5 < 4/6
3. This could also be done by putting in decimal form:
0.6 ?>? 0.666...
This is quicker....of course it should be:
0.6 < 0.666.....
4. Another way is to manipulate the equation to get integers on both sides
multiply both sides by 5
5* 3/5 ?>? 4/6* 5
3 ?>? 20/6
multiply both sides by 6
6*3 ?>? (20/6) * 6
18 ?>? 20
we know that 18 not greater than 20 so it should be written as:
18 < 20
done
this can be done in many ways:
1. Number line(can't really display it here)
2. Use least common multiple on of the denominators so we can force them to be the same
you can start with the product of them:
5 * 6 = 30
so we multiply the left side of the inequality by 6/6 (it must be equivalent to 1 in order to maintain balance) and the right side by 5/5
(6/6)(3/5) ?>? (5/5)(4/6)
18/30 ?>? 20/30
so we know that 20 > than 18, so the answer to the question is NO
it should be:
3/5 < 4/6
3. This could also be done by putting in decimal form:
0.6 ?>? 0.666...
This is quicker....of course it should be:
0.6 < 0.666.....
4. Another way is to manipulate the equation to get integers on both sides
multiply both sides by 5
5* 3/5 ?>? 4/6* 5
3 ?>? 20/6
multiply both sides by 6
6*3 ?>? (20/6) * 6
18 ?>? 20
we know that 18 not greater than 20 so it should be written as:
18 < 20
done
