(-3-2)^2 + (5--4)^2
=
(-5)^2 + (9)^2
=25 + 81
= 106
So d=Square Root of 106
=
(-5)^2 + (9)^2
=25 + 81
= 106
So d=Square Root of 106
Can You Find The Length Of The Line Segment With Endpoints (2, -4) And (-3, 5)?
The formula for distance is d2 = (x2-x1)2 + (y2-y1)2
let x1 = 2
x2 = -3
y1 = -4
y2 = 5
putting in the formula we get
d2= (-3-2)2 + (5+4)2
d2= 106
d= 10.29563014098700031579
let x1 = 2
x2 = -3
y1 = -4
y2 = 5
putting in the formula we get
d2= (-3-2)2 + (5+4)2
d2= 106
d= 10.29563014098700031579
(-3-2)^2+ (5--4)^2
If EF=2x, FG=5x, and EG=8x+1 what is the value of x?