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How To Do 2 Stage Equation With Brackets?

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Oddman Profile
Oddman answered
Solving any equation involves plotting a strategy to isolate the variable on one side of the equal sign. For these equations, you can "undo" what has been "done" to the variable.  1. 6(x-3) = 18 My guess is that you call this a "stage 2 equation" because it takes  two steps to solve it. You solved equations like this when you first  learned to multiply. You had, for example, one that looked like    6*___ = 18  Now, you know immediately that the blank ___ must be filled with 3 to make 6*3 = 18. This just means that the value of the stuff in brackets, that is (x - 3), is 3.    Compare  6*___ = 18     to     6*(x-3) = 18 Thus, the problem reduces to      (x - 3) = 3  You had problems like this when you first learned to add.    ___ - 3 = 3  Now, you know immediately that ___ must be filled with 6 . This is the value of x.  Here is an explanation in somewhat more formal terms. In the first example, we have subtracted 3 from the variable x and then multiplied the result by 6. To solve the equation, you divide the equation by 6, then add 3 to the result.   6(x - 3) = 18    (your original equation)   (6(x - 3))/6 = 18/6    (divide the left side by 6, and divide the right side by 6)   (x - 3)*(6/6) = 18/6    (rearrange the left side so we can see how to "cancel" the 6s)   (x - 3)*1 = 18/6    (recognize that 6/6 = 1)   x - 3 = 18/6    (recognize that anything times 1 is that thing)   x - 3 = 3    (compute 18/6 = 3. Thus ends the first step of dividing the equation by 6. You will quickly learn to get to this point without the intermediate stuff.)    (x - 3) + 3 = (3) + 3    (add 3 to both sides of the equation)   x + (-3 + 3) = 3 + 3    (regroup so we can "cancel" the 3s)   x + 0 = 3 + 3    (recognize that adding a number to its opposite gives 0)   x = 3 + 3    (recognize that anything plus 0 is that thing)   x = 6    (compute 3+3 = 6. Thus ends the second step of adding 3 to the equation. Here is our answer.)  2. 3(x+4)=15 Divide by 3   (x + 4) = 5    (the multiplier of 3 disappears from the left, and the right is a factor of 3 smaller.) Subtract 4   x = 1    (same as fill in the blank of ___ + 4 = 5)  3.  4(x+2)=16 Divide by 4   (x + 2) = 4 Subtract 2   x = 2    (same as fill in the blank of ___ + 2 = 4)
Anonymous Profile
Anonymous answered
You have to distribute the coefficient(6). So in 6(x-3)=18, it would be 6x-18=18, then solve the equation. In a(b+c), it is also equal to ab+ac

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