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If In A Triangle ABC Cos 2 A + Cos 2 B + Cos 2 C = 1, Then Angle A?

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Oddman answered
Perhaps you have
  because[A]^2 + because[B]^2 + because[C]^2 = 1
Two of the angles must be complements of each other. The third angle will be a right angle (90°). The equation is symmetrical in all of the variables, so you can choose angle A to be anything you like in the range 0 to 90°.

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