I can see at least 4 interpretations...

5(x-1) = 2(x+3) (twice (the same number increased by 3), "the difference of a number and 1" = x-1)

5x-5 = 2x+6

3x = 11

x = 11/3

Or

5(x-1) = 2x+3 ((twice the same number) increased by 3)

5x - 5 = 2x + 3

3x = 8

x = 8/3

Or

5(1-x) = 2(x+3) ("the difference of a number and 1" = 1-x)

5-5x = 2x+6

-1 = 7x

x = -1/7

Or

5(1-x) = 2x+3

5-5x = 2x+3

2 = 7x

x = 2/7

English is a terrible language for writing such problems. "The difference of a number and 1" could be taken as (n-1), (1-n) or |n-1|. |n-1| =n-1 for n>1, and 1-n for n<1.

5(x-1) = 2(x+3) (twice (the same number increased by 3), "the difference of a number and 1" = x-1)

5x-5 = 2x+6

3x = 11

x = 11/3

Or

5(x-1) = 2x+3 ((twice the same number) increased by 3)

5x - 5 = 2x + 3

3x = 8

x = 8/3

Or

5(1-x) = 2(x+3) ("the difference of a number and 1" = 1-x)

5-5x = 2x+6

-1 = 7x

x = -1/7

Or

5(1-x) = 2x+3

5-5x = 2x+3

2 = 7x

x = 2/7

English is a terrible language for writing such problems. "The difference of a number and 1" could be taken as (n-1), (1-n) or |n-1|. |n-1| =n-1 for n>1, and 1-n for n<1.