Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?
Given Two Rectangles, One With Length = L And Width = W, And The Second Rectangle With Length = 2l And Width = 4w. How Much Larger Will The Perimeter Of The Second Rectangle Be Than The Perimeter Of The First Rectangle?
The difference in perimeters is found by
P1 = 2(L+W)
P2 = 2(2L + 4W)
P2 - P1 = (2(2L+4W)) - (2(L+W))
= 4L + 8W - 2L - 2W
= 2L + 6W
P1 = 2(L+W)
P2 = 2(2L + 4W)
P2 - P1 = (2(2L+4W)) - (2(L+W))
= 4L + 8W - 2L - 2W
= 2L + 6W
