Given two rectangles, one with length = *l* and width = *w*, and the second rectangle with length = 2*l* and width = 4*w*. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?

# Given Two Rectangles, One With Length = L And Width = W, And The Second Rectangle With Length = 2l And Width = 4w. How Much Larger Will The Perimeter Of The Second Rectangle Be Than The Perimeter Of The First Rectangle?

The difference in perimeters is found by

P

P

P

= 4L + 8W - 2L - 2W

= 2L + 6W

P

_{1}= 2(L+W)P

_{2}= 2(2L + 4W)P

_{2}- P_{1}= (2(2L+4W)) - (2(L+W))= 4L + 8W - 2L - 2W

= 2L + 6W