Area = width * height
Let us say the similarity is in the width. Call it 5 inches
A = 5 in * 3 in
= 15 in^2
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A = 5 in * 9 in
= 45 in^2
======As you should have guessed the area of the second rectangle is 3 times as large as the first rectangle.
If the two rectangles are similar, then the ratio of the side of the 3 inch to the width of the 3 inch must equal the ratio of the side of the 9 inch to the width of the 9 inch
To state that mathematically 3/x = 9/y from which y = 3x for this "family" of similar rectangles.
So if x = 4, y = 12 and the area of one is 12 and the area of the second must be 108.
And if x = 5, y = 15 and the areas are 20 and 135
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