Let ABC be the triangle,where AB be the 1st side,BC be the 2nd side and AC be the 3rd side.
According to question,
If x be the length of 2nd side,then
1st side=x+5
3rd side=4x
Now,
Perimeter of the triangle=65 meters
or,AB+BC+AC=65
or,x+5+x+4x=65
or,6x=65-5
or,x=60/6=10
i.e.The 2nd side is 10m.ans
According to question,
If x be the length of 2nd side,then
1st side=x+5
3rd side=4x
Now,
Perimeter of the triangle=65 meters
or,AB+BC+AC=65
or,x+5+x+4x=65
or,6x=65-5
or,x=60/6=10
i.e.The 2nd side is 10m.ans