Let ABC be the triangle,where AB be the 1st side,BC be the 2nd side and AC be the 3rd side.

According to question,

If x be the length of 2nd side,then

1st side=x+5

3rd side=4x

Now,

Perimeter of the triangle=65 meters

or,AB+BC+AC=65

or,x+5+x+4x=65

or,6x=65-5

or,x=60/6=10

i.e.The 2nd side is 10m.ans

According to question,

If x be the length of 2nd side,then

1st side=x+5

3rd side=4x

Now,

Perimeter of the triangle=65 meters

or,AB+BC+AC=65

or,x+5+x+4x=65

or,6x=65-5

or,x=60/6=10

i.e.The 2nd side is 10m.ans