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Consider A Right Triangle That Has These Dimensions: The Side Opposite Angle A Is 6 Meters And The Side Adjacent Angle A Is 8 Meters. How Long Is The Hypotenuse?

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3 Answers

Fangju Fangju Profile
Fangju Fangju answered
Set the hypotenuse is x.
6^2+8^2=x^2,x=10 meters.
Oddman Profile
Oddman answered
This "3-4-5" triangle has a hypotenuse length of 10 meters.

√(6^2 + 8^2) = 10
Anonymous Profile
Anonymous answered
If you have a triangle and its like this right triangle | and the shortest leg is the 6 and lets say the other leg that is longer or adjacent to it is 8 which across from it is the hypotnuse.

Well for these types of problems you always need the a^2+b^2=c^2 formula

so in this sense the a^2 always applies to the shortest leg and the b^2 always applies to the adjacent leg and the c^2 always applies to the hypotenuse leg.

So with the information we have it would be 8^2+6^2 = c^2

so 8^2= 64 +  6^2=36   so you have so far 64 + 36 =100 you take the square root of that

so square root of a 100 is  10. You know its your hypotenuse because it is always the longest length for the leg. If your value is shorter than your other legs then you know you are wrong. It is always the longest.

Hope this helps if you need more examples or etc. Please contact me :)

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