Set the hypotenuse is x.
6^2+8^2=x^2,x=10 meters.
6^2+8^2=x^2,x=10 meters.
Consider A Right Triangle That Has These Dimensions: The Side Opposite Angle A Is 6 Meters And The Side Adjacent Angle A Is 8 Meters. How Long Is The Hypotenuse?
This "3-4-5" triangle has a hypotenuse length of 10 meters.
√(6^2 + 8^2) = 10
√(6^2 + 8^2) = 10
If you have a triangle and its like this right triangle | and the shortest leg is the 6 and lets say the other leg that is longer or adjacent to it is 8 which across from it is the hypotnuse.
Well for these types of problems you always need the a^2+b^2=c^2 formula
so in this sense the a^2 always applies to the shortest leg and the b^2 always applies to the adjacent leg and the c^2 always applies to the hypotenuse leg.
So with the information we have it would be 8^2+6^2 = c^2
so 8^2= 64 + 6^2=36 so you have so far 64 + 36 =100 you take the square root of that
so square root of a 100 is 10. You know its your hypotenuse because it is always the longest length for the leg. If your value is shorter than your other legs then you know you are wrong. It is always the longest.
Hope this helps if you need more examples or etc. Please contact me :)
Well for these types of problems you always need the a^2+b^2=c^2 formula
so in this sense the a^2 always applies to the shortest leg and the b^2 always applies to the adjacent leg and the c^2 always applies to the hypotenuse leg.
So with the information we have it would be 8^2+6^2 = c^2
so 8^2= 64 + 6^2=36 so you have so far 64 + 36 =100 you take the square root of that
so square root of a 100 is 10. You know its your hypotenuse because it is always the longest length for the leg. If your value is shorter than your other legs then you know you are wrong. It is always the longest.
Hope this helps if you need more examples or etc. Please contact me :)