A horse starts to chase a dog that has left the stable two hours earlier. The horse runs at an average speed of 2km/hr. It crosses a 10-metre road, two small ponds 3 metres deep, and finally runs along two small streets of 200 metres long.After?

The given question is incomplete..the correct question is

A horse starts to chase a dog that has left the stable two hours earlier. The horse runs at an average speed of 2km/hr.  (It crosses a 10-metre road, two small ponds 3 metres deep, and finally runs along two small streets of 200 metres long=irrelavent data). After traveling 6 hrs, 2hrs after sunset, it catches the dog. Compute the speed of the dog in Km/hr?
Ans:starting of the question is given to waste our time.its useless

horse's average speed =2kmphhorse catches the dog after 6 hours.sototal distance travelled by horse=>>distance=velocity*time   =2kmph*6
=12km
but the dog started 2 hours before(read the question)
so total time taken to travel 12 km by dog is=6+2=8 hours.
By using basic
distance=velocity*time formula we can get the velocity of dog
12=velocity*8velocity=12/8=1.5kmph

thanked the writer. 