You can solve for y, then substitute x=-3, or you can substitute x=-3 and solve for y. Let's do it the second way first.
2x -3y = 9 (the original equation)
2(-3) -3y = 9 (equation with -3 substituted for x)
3(-2 -y) = 3*3 (factor out 3)
-2 -y = 3 (divide both sides by 3)
-y = 3 + 2 (add 2 to both sides)
y = -5 (multiply both sides by -1)
_____
Solve for y ...
2x -3y = 9
2x = 9 + 3y (add 3y to both sides)
2x -9 = 3y (subtract 9 from both sides)
(2/3)x - 3 = y (divide both sides by 3)
(2/3)(-3) -3 = y (substituted -3 for x)
-2 -3 = y (perform the multiplication)
-5 = y (perform the addition)
2x -3y = 9 (the original equation)
2(-3) -3y = 9 (equation with -3 substituted for x)
3(-2 -y) = 3*3 (factor out 3)
-2 -y = 3 (divide both sides by 3)
-y = 3 + 2 (add 2 to both sides)
y = -5 (multiply both sides by -1)
_____
Solve for y ...
2x -3y = 9
2x = 9 + 3y (add 3y to both sides)
2x -9 = 3y (subtract 9 from both sides)
(2/3)x - 3 = y (divide both sides by 3)
(2/3)(-3) -3 = y (substituted -3 for x)
-2 -3 = y (perform the multiplication)
-5 = y (perform the addition)