Is this a trapezoid (Br: Trapezium) where two bases are paralell? Is one side perpendicular to the paralell bases (= height)? If both of these criteria are met, then the formula is: Area = [(base + base) x (height)]/2. If neither side is perpendicular to the paralell bases then the formula is: [(a+b)/(4(b-a))] x square root of: [(-a+b+c+d)(a-b+c+d)(a-b+c-d)(a-b-c+d)]. If this is just a quadrilateral with no paralell or perpendicular sides, you need Oddman to the rescue!

We need a bit more information, do you have an angle or two to share with us?

Do we need angles Ray can't we just divide it into two triangles and do it that way,or am I missing something?

If it is a trapezium, the side of length 75 is parallel to the side of length 15. The distance between them is about 19.7423 ft, so the area is about

The exact area of the trapezium is

(3/8)√5612519 ft^2

**888.403 ft^2**. (The short diagonal can be computed from the Law of Cosines as (19√5)/2 ft.) If it is any other shape, additional information is needed.The exact area of the trapezium is

(3/8)√5612519 ft^2