FORMULA FOR THE VOLUME OF TRIANGULAR PYRAMID IS :
Volume = 1/3 × [Base Area] × Height
A triangular pyramid has has 4 Faces , The 3 Side Faces are Triangles, The Base is also a Triangle , It has 4 Vertices (corner points), It has 6 Edges
======
Volume = 180 cubic cm
Height = 12 cm.
We can calculate the base area. I.e.
Base area = 3 x volume / height
= 3 x 180 / 12
= 45 cm square.
Base area = 1/ 2 x base x height
45 = 1/2 x 6 x height (height of base triangle)
45x2 / 6 = height
height = 90/6
height = 15
now we know the height and base of base triangle. I.e. 15 and 6
one of the sides of the base triangle can be calculated through pythagorean theorem.
H^2 = p^2 + b^2
h^2 = 15^2 + 3^2
h^2 = 225+9
h= 15.297 answer.
Volume = 1/3 × [Base Area] × Height
A triangular pyramid has has 4 Faces , The 3 Side Faces are Triangles, The Base is also a Triangle , It has 4 Vertices (corner points), It has 6 Edges
======
Volume = 180 cubic cm
Height = 12 cm.
We can calculate the base area. I.e.
Base area = 3 x volume / height
= 3 x 180 / 12
= 45 cm square.
Base area = 1/ 2 x base x height
45 = 1/2 x 6 x height (height of base triangle)
45x2 / 6 = height
height = 90/6
height = 15
now we know the height and base of base triangle. I.e. 15 and 6
one of the sides of the base triangle can be calculated through pythagorean theorem.
H^2 = p^2 + b^2
h^2 = 15^2 + 3^2
h^2 = 225+9
h= 15.297 answer.
