What is an equation in standard form for: Y-1= 5 over 6 (x-4)?

These series of questions appear to be dealing with straight line functions. 

Therefore,  assume the equation is y - 1 = (5/6)(x -4).

If the function is assumed to be y - 1 = 5/[6(x - 4)], the function would be a natural log function, which is much more difficult to develop.

So
y - 1 = (5/6)( x - 4)        First, clear the parenthesis

y - 1 = (5/6)x  - (5/6)4

y -1 = (5/6)x - 10/3          combine the like terms by adding 1 to both sides

y = (5/6)x - 10/3 + 3/3  = (5/6)x - 7/3

So the slope m = 5/6, and the y intercept is -7/3

y = (5/6)x - 7/3