**lakeesha Hennessy Williams**answered

To find out whether a fraction is in its simplest form, you simply need to figure out whether there are any common numbers that the numerator and denominator can be divided into evenly.

Keep reading to find out how this is done:

The best way to demonstrate how to work out whether fractions are in their simplest form would be to use an example.

I'll use the fraction 8/12.

What do we know already?

With the example of 8/12: The numbers 1, 2, and 4 fit into 8. The numbers 1, 2, 3, 4, and 6 fit into 12.

We don't count the number 1 (because that fits into every number evenly), which leaves us with two numbers that both 8 and 12 can be divided by: 2 and 4.

You need to pick the highest common number (also known as the lowest common

In the case of 8/12, 8 divided by 4 is 2. 12 divided by 4 is 3. That means that 8 over 12 in its simplest form is actually 2 over 3, or 2/3.

For more examples of how to simplify fractions, why not check out mathisfun.com.

Keep reading to find out how this is done:

**Is this fraction in its simplest form?**The best way to demonstrate how to work out whether fractions are in their simplest form would be to use an example.

I'll use the fraction 8/12.

What do we know already?

- The number 8 is the numerator
- The number 12 is the denominator
- There are a couple of numbers that fit into both 8 and 12 without leaving any left-overs.

With the example of 8/12: The numbers 1, 2, and 4 fit into 8. The numbers 1, 2, 3, 4, and 6 fit into 12.

We don't count the number 1 (because that fits into every number evenly), which leaves us with two numbers that both 8 and 12 can be divided by: 2 and 4.

You need to pick the highest common number (also known as the lowest common

*factor*), and divide both the numerator and the denominator by it.In the case of 8/12, 8 divided by 4 is 2. 12 divided by 4 is 3. That means that 8 over 12 in its simplest form is actually 2 over 3, or 2/3.

For more examples of how to simplify fractions, why not check out mathisfun.com.