Too many uses of "digit"....

# Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number?

I'll solve that problem for you, but only if you give me some money.

Yes

This link will help you.

https://www.algebra.com/algebra/homework/word/numbers/Numbers_Word_Problems.faq.question.910189.html

5(x + y) = 10x+y - 13.......(1)

4(x + y) = 10y+x - 21.........(2)

After solving it you will get the value of **x=9** and **y=8**

For checking put the values in the equations

4(9 + 8) = 80+9 - 21

4(17) = 89-21

68 = 68

I hope it'll help.