Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number?

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6 Answers

Ray Dart Profile
Ray Dart answered

Too many uses of "digit"....

1 Person thanked the writer.
Allison Lee
Allison Lee commented
thats what confuses me. Its an actual question
Allison Lee
Allison Lee commented
all I know is that its supposed to be a system of equations
Ray Dart
Ray Dart commented
Sorry Allison. It is a question, set by an idiot who had nothing better to do that day. Algebra is your help here. Give the two digits names. The leftmost one could be L and the rightmost one R.

From that you ought to be able to create equations.
If you still need help (and try to work with us here), come back tomorrow.
Rooster Cogburn Profile
Rooster Cogburn , Rooster Cogburn, answered

Yes

PJ Stein Profile
PJ Stein answered

This link will help you.

https://www.algebra.com/algebra/homework/word/numbers/Numbers_Word_Problems.faq.question.910189.html

Deepak Suwalka Profile
Deepak Suwalka answered

5(x + y) = 10x+y - 13.......(1)

4(x + y) = 10y+x - 21.........(2)

After solving it you will get the value of x=9 and y=8

For checking put the values in the equations

4(9 + 8) = 80+9 - 21

4(17) = 89-21

68 = 68

I hope it'll help.

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