Solve By Factoring And Using The Principle Of Zero Products. Show Work (x + 6)(x - 1) = 18 Can Some One Show Me The Steps I Am Lost At This One?
You need to multiply out the left side, subtract 18, then factor the result.
(x+6)(x-1) = 18
x^2 - x + 6x - 6 = 18 (multiply out the left side. You can use the FOIL method, if you are comfortable with that. Otherwise, just make use of the distributive property.)
x^2 + 5x - 24 = 0 (subtract 18 from both sides)
x^2 + 8x - 3x - 24 = 0 (we need factors of 24 whose difference is 5. 3 and 8 will do.)
x(x+8) - 3(x+8) = 0 (factor the first two terms and the last two terms)
(x-3)(x+8) = 0 (factor out the common factor from the above result)
The solution to this is the set of values for x that will make these factors zero. They are
x = 3, x = -8.
(x+6)(x-1) = 18
x^2 - x + 6x - 6 = 18 (multiply out the left side. You can use the FOIL method, if you are comfortable with that. Otherwise, just make use of the distributive property.)
x^2 + 5x - 24 = 0 (subtract 18 from both sides)
x^2 + 8x - 3x - 24 = 0 (we need factors of 24 whose difference is 5. 3 and 8 will do.)
x(x+8) - 3(x+8) = 0 (factor the first two terms and the last two terms)
(x-3)(x+8) = 0 (factor out the common factor from the above result)
The solution to this is the set of values for x that will make these factors zero. They are
x = 3, x = -8.
