Suppose That The Width Of A Rectangle Is 5 Inches Shorter Than The Length And The Perimeter Of The Rectangle Is 50. Set Up An Equation For The Perimeter Involving Only L, The Lenght Of The Rectangle. Solve This Equation Algebraically To Find The?

The perimeter is twice the sum of the length and width, but the width is the length less 5 inches. Let "L" represent the length.

P = 2*(L + (L - 5 in))    (your equation)

50 in = 2(2L - 5 in)
25 in = 2L - 5 in
30 in = 2L
30/2 in = L = length = 15 in.

L - 5 in = (15 - 5) in = 10 in = width