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How Do I Calculate The Percentage Of A Solution?

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Anonymous Profile
Anonymous answered
10% 100
simon wagstaff Profile
simon wagstaff answered
Assume that the volume of the mixture = 1liter, x is the number of mole of C2HF5 and y is the number of mol of the second one

The mass of the mixture[ m (mixture)] = V.d = 2.76*1=2.76 (g)
The number of mole of the mixture = pV/RT = 0.0378 (mol)

m(mixture) is the sum of the mass of 2 gases :210x + 52y = 2.76
n(mixture) = x + y = 0.0378
===>x =0.005 and y=0.0328

It is due to the fact that in a mixture of gases, %V = %n
===> %V of the first one = x*100/(x+y) = 0.005*100/0.0378
= 13.2%
%V of the second one = 100% - 13,2% = 86.8%

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