10% 100
How Do I Calculate The Percentage Of A Solution?
Assume that the volume of the mixture = 1liter, x is the number of mole of C2HF5 and y is the number of mol of the second one
The mass of the mixture[ m (mixture)] = V.d = 2.76*1=2.76 (g)
The number of mole of the mixture = pV/RT = 0.0378 (mol)
m(mixture) is the sum of the mass of 2 gases :210x + 52y = 2.76
n(mixture) = x + y = 0.0378
===>x =0.005 and y=0.0328
It is due to the fact that in a mixture of gases, %V = %n
===> %V of the first one = x*100/(x+y) = 0.005*100/0.0378
= 13.2%
%V of the second one = 100% - 13,2% = 86.8%
The mass of the mixture[ m (mixture)] = V.d = 2.76*1=2.76 (g)
The number of mole of the mixture = pV/RT = 0.0378 (mol)
m(mixture) is the sum of the mass of 2 gases :210x + 52y = 2.76
n(mixture) = x + y = 0.0378
===>x =0.005 and y=0.0328
It is due to the fact that in a mixture of gases, %V = %n
===> %V of the first one = x*100/(x+y) = 0.005*100/0.0378
= 13.2%
%V of the second one = 100% - 13,2% = 86.8%
