(y - y₁) = m(x - x₁)
m = tanθ
m = tan 135
m = -1
(x₁, y₁) = (-2, 3)
(y - 3) = -1[x - (-2)]
y - 3 = -1[x + 2]
y - 3 = -x -2
y =-x-2+3
y = -x + 1
How do you find the equation of a straight line which passes through the point (-2,3) and makes an angle of 135° with the positive direction of the x-axis?