Algebraically:

X + (x + 1) + (x + 2) = 60

3x + 3 = 60 (collect terms)

3x + 3 - 3= 60 - 3 (substract 3 from both sides)

3x = 57 (simplify)

3x/3 = 57/3 (divide by 3 on both sides)

x = 19

x + 1 = 20

x + 2 = 21

Final Answer: The sum of the consecutive numbers 19,20 and 21 = 60.

X + (x + 1) + (x + 2) = 60

3x + 3 = 60 (collect terms)

3x + 3 - 3= 60 - 3 (substract 3 from both sides)

3x = 57 (simplify)

3x/3 = 57/3 (divide by 3 on both sides)

x = 19

x + 1 = 20

x + 2 = 21

Final Answer: The sum of the consecutive numbers 19,20 and 21 = 60.