Algebraically:
X + (x + 1) + (x + 2) = 60
3x + 3 = 60 (collect terms)
3x + 3 - 3= 60 - 3 (substract 3 from both sides)
3x = 57 (simplify)
3x/3 = 57/3 (divide by 3 on both sides)
x = 19
x + 1 = 20
x + 2 = 21
Final Answer: The sum of the consecutive numbers 19,20 and 21 = 60.
X + (x + 1) + (x + 2) = 60
3x + 3 = 60 (collect terms)
3x + 3 - 3= 60 - 3 (substract 3 from both sides)
3x = 57 (simplify)
3x/3 = 57/3 (divide by 3 on both sides)
x = 19
x + 1 = 20
x + 2 = 21
Final Answer: The sum of the consecutive numbers 19,20 and 21 = 60.