Let the three consecutive odd numbers are x, x + 2 and x + 4. The sum of three consecutive odd numbers is -27.
Sum of consecutive odd numbers = -27
x + (x + 2) + (x + 4 ) = -27
x + x + 2 + x + 4 = -27
3x + 6 = -27
subtracting 6 on both sides
3x + 6 - 6 = -27 - 6
3x = -33
Diving by three on both sides
3x / 3 = -33/3
x = -11
First number = -11
Second number = x + 2 = -11 + 2 = -9
Third number = x + 4 = -11 + 4 = -7
Sum of consecutive odd numbers = -27
x + (x + 2) + (x + 4 ) = -27
x + x + 2 + x + 4 = -27
3x + 6 = -27
subtracting 6 on both sides
3x + 6 - 6 = -27 - 6
3x = -33
Diving by three on both sides
3x / 3 = -33/3
x = -11
First number = -11
Second number = x + 2 = -11 + 2 = -9
Third number = x + 4 = -11 + 4 = -7
