Let the three consecutive odd numbers are x, x + 2 and x + 4. The sum of three consecutive odd numbers is -27.

Sum of consecutive odd numbers = -27

x + (x + 2) + (x + 4 ) = -27

x + x + 2 + x + 4 = -27

3x + 6 = -27

subtracting 6 on both sides

3x + 6 - 6 = -27 - 6

3x = -33

Diving by three on both sides

3x / 3 = -33/3

x = -11

First number = -11

Second number = x + 2 = -11 + 2 = -9

Third number = x + 4 = -11 + 4 = -7

Sum of consecutive odd numbers = -27

x + (x + 2) + (x + 4 ) = -27

x + x + 2 + x + 4 = -27

3x + 6 = -27

subtracting 6 on both sides

3x + 6 - 6 = -27 - 6

3x = -33

Diving by three on both sides

3x / 3 = -33/3

x = -11

First number = -11

Second number = x + 2 = -11 + 2 = -9

Third number = x + 4 = -11 + 4 = -7