5t

(5t)(t - 2) = 0

Either t5 = 0 or t - 2 = 0 which means that t = 0 or t = 2.

x

x

x(x-5) -2(x-5)=0

(x-5)(x-2)=0

Therefore, either (x-5)=0 or (x-2)=0 and in this case x = 5 or x = 2.

^{2}-10t = 0(5t)(t - 2) = 0

Either t5 = 0 or t - 2 = 0 which means that t = 0 or t = 2.

x

^{2}-3x -10=0x

^{2}-5x -2x-10=0x(x-5) -2(x-5)=0

(x-5)(x-2)=0

Therefore, either (x-5)=0 or (x-2)=0 and in this case x = 5 or x = 2.