Firstly, the width/length of the square would be 32cm/4 = 8cm.

Now, if we cut the square in half along the diagonal, we get a right angle triangle. This diagonal would be the hypotenuse of a right angle of a triangle. We can further solve this problem using pythagoras' theorem. We can use the measurements of 8cm . Hence:

Pythagoras theorem: C

c

SQRT(c

c = 11.3137085

Final answer: The length of the diagonal would be 11.3137085

Now, if we cut the square in half along the diagonal, we get a right angle triangle. This diagonal would be the hypotenuse of a right angle of a triangle. We can further solve this problem using pythagoras' theorem. We can use the measurements of 8cm . Hence:

Pythagoras theorem: C

^{2}= a^{2}+ b^{2}^{}c

^{2 }= 8^{2}+ 8^{2 }= 64 + 64 = 128 (plug in the values and simplify)SQRT(c

^{2})^{ }= SQRT(128)c = 11.3137085

Final answer: The length of the diagonal would be 11.3137085