Firstly, the width/length of the square would be 32cm/4 = 8cm.
Now, if we cut the square in half along the diagonal, we get a right angle triangle. This diagonal would be the hypotenuse of a right angle of a triangle. We can further solve this problem using pythagoras' theorem. We can use the measurements of 8cm . Hence:
Pythagoras theorem: C2= a2+ b2
c2 = 82 + 82 = 64 + 64 = 128 (plug in the values and simplify)
SQRT(c2) = SQRT(128)
c = 11.3137085
Final answer: The length of the diagonal would be 11.3137085
Now, if we cut the square in half along the diagonal, we get a right angle triangle. This diagonal would be the hypotenuse of a right angle of a triangle. We can further solve this problem using pythagoras' theorem. We can use the measurements of 8cm . Hence:
Pythagoras theorem: C2= a2+ b2
c2 = 82 + 82 = 64 + 64 = 128 (plug in the values and simplify)
SQRT(c2) = SQRT(128)
c = 11.3137085
Final answer: The length of the diagonal would be 11.3137085
