Solve the following inequality: 2⁄3(6x − 9) + 4 > 5x + 1?

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Oddman Profile
Oddman answered
2/3(6x - 9) + 4 > 5x + 1 4x - 6 + 4 > 5x + 1    (eliminate parentheses using the distributive property) -2 > x + 1    (subtract 4x) -3 > x    (subtract 1)  Check   For x = -3, we expect the left side equal to the right side (inequality NOT satisfied)   2/3(6(-3)-9) + 4 > 5(-3) + 1   2/3(-18-9) + 4 > -15 + 1   2/3(-27) + 4 > -14   -18 + 4 > -14    (the inequality is not satisfied, as expected)    For x = -4, we expect the inequality to be satisfied.   2/3(6(-4)-9) + 4 > 5(-4) + 1   2/3(-24-9) + 4 > -20 + 1   2/3(-33) + 4 > -19   -22 + 4 > - 19    (the inequality is satisfied, as expected)
Du-Rhone Emilie Profile
Du-Rhone Emilie answered
2(2x+3)+4>5x+1
4x+6+4>5x+1
4x+10>5x+1
4x-5x>1-10
-x>-9
x>9

thanked the writer.
Oddman
Oddman commented
Somehow -9/3 became +3.
lanah galvan
lanah galvan commented
Yeah no kidding....but i dont understand how to distribute the faction tho....can someone explain that to me

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